Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An air core solenoid has $1000$ turns and is one meter long. Its cross - sectional area is $10 cm ^{2}$. Its self inductance is:

Electromagnetic Induction

Solution:

$L=\frac{\mu_{0} N^{2} A}{l}$
$L=\frac{4 \pi \times 10^{-7}\left(10^{3}\right)^{2} \times 10^{-3}}{1}$
$L =\frac{4 \times 3.14 \times 10^{-7} \times 10^{6} \times 10^{-3}}{1}$
$L =1.256 \times 10^{-3}$
$\Rightarrow 1.256\, mH$