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Q. An air bubble of radius $0.1\, cm$ is in a liquid having surface tension $0.06\, N/m$ and density $10^3\, kg/m^3$. The pressure inside the bubble is 1100 $Nm^{-2}$ greater than the atmospheric pressure. At what depth is the bubble below the surface of the liquid ? $(g = 9.8 \,ms^{-2})$

JEE MainJEE Main 2014Mechanical Properties of Fluids

Solution:

$h\,dg + \frac{LT}{r} = 1100$
$h \times 10^{3} \times 4.8 = 1100 - \frac{2\times 0.06}{0.1\times 10^{-2}}$
$= 980$
$h = \frac{980}{9.8\times 10^{3}} = 0.1\,m$