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Q.
An air bubble in a glass slab (R.I. = 1.5) . appears to be at 0.06 m and 0.04 m when viewed normally from the two opposite sides. The thickness, in m, of the slab is
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Solution:
Refractive index of slab, $\mu = 1.5$
Total apparent length in the glass
$= 0.06 + 0.04 = 0.10 \: m$.
Thickness of the slab,
$t = \mu \times $ Apparent length in the glass
$= 1 .5 \times 0.10 = 0.15 \: m$.