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  4. An aeroplane, with its wings spread 10 m, is flying at a speed of 180 km / h in a horizontal direction. The total intensity of earth's field at that part is 2.5 × 10-4 Wb / m 2 and the angle of dip is 60° . The emf induced between the tips of the plane wings will be :-

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Q. An aeroplane, with its wings spread $10 m$, is flying at a speed of $180 km / h$ in a horizontal direction. The total intensity of earth's field at that part is $2.5 \times 10^{-4} Wb / m ^{2}$ and the angle of dip is $60^{\circ} .$ The emf induced between the tips of the plane wings will be :-

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Solution:

$\in=[\vec{ B } \vec{ V } \vec{ L }]= BVL \sin \theta$
$=\left(2.5 \times 10^{-4} T \right)\left(180 \times \frac{5}{18} m / s \right)(10 m ) \sin 60^{\circ}$
$=108.25 \times 10^{-3} V$