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Q. An aeroplane is flying horizontally with a velocity of 216 km/h and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance)

AMUAMU 1998

Solution:

: Horizontal velocity of aeroplane, $ u=\frac{216\times 1000}{60\times 60}=60\,m/s $ Time of flight, $ T=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2\times 1960}{9.8}}=20\,s $ Horizontal range, $ =AB=nT $ $ =60\times 20=1200m $ .