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Q. An acid-base indicator HIn in a buffer of $pH = pK _{ In }-1$ is ionized to the extent of about ____

Equilibrium

Solution:

$pH = pK _{ \text{In} }+\frac{\left[ \text{In }^{-}\right]}{[ \text{HIn} ]}=\left( pK _{\text{ In} }-1\right)$
$\log \frac{\left[ \text{In} ^{-}\right]}{[ \text{Hin} ]}=-1 \longrightarrow \frac{\left[ \text{In} ^{-}\right]}{[ \text{Hln }]}=0.1$
$\%$ ionized $=\frac{0.1 \times 100}{0.1+1}=\frac{10}{1.1}=9.1: 9.0$