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  4. An ac source is of (200/√2) V, 50 Hz . The value of voltage after (1/600) s from the start is

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Q. An ac source is of $\frac{200}{\sqrt{2}}\,V$, $50\,Hz$ . The value of voltage after $\frac{1}{600}\,s$ from the start is

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Solution:

$V_{m}=\frac{200}{\sqrt{2}}\,V_{rms}$
$V_{0}=\sqrt{2}\,V_{rms}=\sqrt{2}\times\frac{200}{\sqrt{2}}=200\,V$
$V=V_{0}\,sin\,2\pi\upsilon t=200\,sin\left(2\pi\times50\times\frac{1}{600}\right)$
$=200\,sin \frac{\pi}{6}=200\times\frac{1}{2}=100\,V$