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  4. An 8 kg metal block of dimensions 16 cm × 8 cm × 6 cm is lying on a table with its face of largest area touching the table. If g=10 m s -2, the minimum amount of work done in making it stand with its length vertical is

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Q. An $8\, kg$ metal block of dimensions $16\, cm \times 8\, cm \times 6\, cm$ is lying on a table with its face of largest area touching the table. If $g=10\, m\, s ^{-2}$, the minimum amount of work done in making it stand with its length vertical is

Work, Energy and Power

Solution:

When face of the largest area is touching the table, height of centre of gravity above the table
$h_{1}=\frac{6}{2}=3\, cm$
With its length vertical, height of centre of gravity would become
$h_{2}=\frac{16}{2}=8\, cm$
Minimum work required
$W=( P.E. )_{2}-( P.E. )_{1}=m g\left(h_{2}-h_{1}\right)$
$\therefore W=\frac{8 \times 10(8-3)}{100}=4 \,J$