Question

Among the following, which is the correct order of decreasing $N-O$ bond length: $NO_{2}^{+}, \, NO_{2}^{-}, \, NO_{3}^{-}$

• A. $NO_{3}^{-}>NO_{2}^{+}>NO_{2}^{-}$
• B. $NO_{3}^{-}>NO_{2}^{-}>NO_{2}^{+}$
• C. $NO_{2}^{+}>NO_{3}^{-}>NO_{2}^{-}$
• D. $NO_{2}^{-}>NO_{3}^{-}>NO_{2}^{+}$

Answer 1

Answer: (B)

Higher the bond order stronger the bond will be , and shorter the bond length.
Bond order $\alpha \frac{1}{Bond \, length}$
$ \, & NO_{2}^{+} & NO_{2}^{-} \\ Bond \, order & 2 & 1.5NO_{3}^{-} \\ 1.33$