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Q.
Among the following the species that is both tetrahedral and diamagnetic is
KVPYKVPY 2012Coordination Compounds
Solution:
In $Ni(CO)_4, Ni$, is in $0$ oxidation number thus,
its electronic configuration is $3d^8 4s^2$.
As $CO$ is a strong field ligand and pairing of electrons occurs thus its configuration
becomes$3d^{10} 4s^0$.
As $Ni(CO)_4$ has $sp^3$ -hybridisation, so its geometry will be tetrahedral.
Also, all the electrons are paired, so it is diamagnetic in nature.