Question

Among $\left[\right.Ni\left(\right.CO\left(\left.\right)_{4}\left]\right.,\left[\right.NiBr_{4}\left(\left]\right.\right)^{2 -},$ $\left[\right.Co\left(\right.NH_{3}\left(\left.\right)_{4}Cl_{2}\left]\right.Cl,$ $Na_{3}\left[\right.CoF_{6}\left]\right.,BaO_{2}$ and $CsO_{2}$ , the total number of diamagnetic compounds is:

• A. 5
• B. 3
• C. 4
• D. 2

Answer 1

Answer: (B)

$\left[\right.Ni\left(\right.CO\left(\left.\right)_{4}\left]\right.-sp^{3}-$ Diamagnetic
$\left[\right.NiBr_{4}\left]\right.^{2 -}-sp^{3}-$ Paramagnetic
$\left[\right.Co\left(\right.NH_{3}\left(\left.\right)_{4}Cl_{2}\left]\right.Cl-d^{2}sp^{3}-$ Diamagnetic
$Na_{3}\left[\right.CoF_{6}\left]\right.-sp^{3}d^{2}-$ Paramagnetic
$BaO_{2}$ i.e. $O_{2}^{2 -}-$ Diamagnetic
$CsO_{2}$ i.e. $O_{2}^{-}-$ Paramagnetic