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  4. Among Me3N, C5H5N and MeCN (Me = methyl group) the electronegativity of N is in the order

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Q. Among $Me_3N, C_5H_5N$ and $MeCN$ ($Me$ = methyl group) the electronegativity of $N$ is in the order

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Solution:

$\because$ In $Me _{3} N \rightarrow N$ is $s p^{3}$-hybrid
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In $C _{5} H _{5} N \rightarrow N$ is $s p^{2}$-hybrid
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and in $MeCN \rightarrow N$ is $s p$-hybrid
Also electronegativity of any element $\alpha \%$ $s$-character in hybrid orbitals.
Thus, order of electronegativity for nitrogen is
$MeCN > C _{5} H _{5} N < Me _{3} N$