1. Tardigrade
  2. Question
  3. Chemistry
  4. Among KO2, AlO2-, BaO2 and NO2+ unpaired electron is present in

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Q. Among $KO_2, AlO_2^-, BaO_2$ and $NO_2^+$ unpaired electron is present in

Chemical Bonding and Molecular Structure

Solution:

$KO_2$ is the only superoxide among the given oxides, therefore it will be paramagnetic due to the presence of an odd electron.