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Q.
Among all cyclic quadrilaterals inscribed in a circle of radius $R$ with one of its angles equal to $120^{\circ}$ Consider the one w ith maximum possible area. Its area is
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Solution:
$ABCD$ is a cyclic quadrilateral
$\angle A=120^{\circ}$
$ABCD$ has maximum area possible
When $\angle B =\angle D=90^{\circ}$
$\therefore $ Area of quadrilateral
$=2 \times \frac{1}{2} \times AD \times DC$
$=2\times \frac{1}{2}\times R \times \sqrt{3}R$
$[\because AD=R, DC= \sqrt{3}R] $
$=\sqrt{3}R^{2}$