Question

Ammonia and chlorine are made to react. If ammonia is in excess, products formed are $A$ and $B$. And when chlorine is in excess the products are $C$ and $D$. $A, B, C$ and $D$ respectively are

• A. $NCl_{3}, HCl$ and $N_{2}, NH_{4}Cl$
• B. $N_{2}, NH_{4}Cl$ and $NCl_{3}, HCl$
• C. $N_{2}, HCl$ and $N_{2}$, $NH_{4}Cl$
• D. $N_{2}$, $NH_{4}Cl$ and $NCl_{3}$, $HCl$

Answer 1

Answer: (B)

When ammonia is in excess:
$2NH_{3}+3Cl_{2} \to N_{2}+3HCl$
$[2NH_{3}+HCl \to NH_{4}Cl]\times 6$
$8 NH_{3}+3Cl_{2} \to N_{2}+6NH_{4}Cl$
When chlorine is in excess:
$NH_{3}+HCl \to NCl_{3}+3HCl$