Thank you for reporting, we will resolve it shortly
Q.
Allyl isocyanide has
Organic Chemistry – Some Basic Principles and Techniques
Solution:
$CH _{2}= CH - CH _{2}- N \equiv C$
In it we find, $5 C - H (\sigma$ bonds $), 1 C - C$ (\sigma bond), $1 C - N (\sigma$ bond $), 1 C = C (1 \sigma$ and $1 \pi$ bonds $)$, i.e., a total of $9 \sigma$ and $3 \pi$ bonds and two non-bonded electrons are present on $C$ - atom of $N \equiv C$ :