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Q. All the energy released from the reaction $X \rightarrow Y , \Delta_{ r } G ^{\circ}=-193\, kJ\, mol ^{-}$is used for oxidizing $M ^{+}$as $M ^{+} \rightarrow M ^{3+}+2 e ^{-}, E ^{\circ}=-0.25\, V$. Under standard conditions, the number of moles of $M ^{+}$oxidized when one mole of $X$ is converted to $Y$ is $\left[ F =96500\, C\, mol ^{-1}\right]$

Electrochemistry

Solution:

$M ^{+} \rightarrow M ^{3+}+2 e ^{-}$
$nM ^{+} \rightarrow nM ^{3+}+2 ne ^{-}\,\, \Delta G ^{\circ}=-2 n\, FE ^{\circ}$
And :
$\left|\Delta_ r G ^{\circ}\right|=\left|\Delta G ^{\circ}\right|$
$\therefore 193 \times 1000=2 \times n \times 96500 \times 0.25$
$n =4$