Question

Alfred Hershey and Martha Chase made a big contribution in proving $DNA$ role as the hereditary molecule. The experiment is shown in the diagram. $A$ and $C$ are the presence or absence of radioactivity detected in cells $B$ and $D$ are the presence or absence of radioactivity detected in supernatant cells. Identify $A, B, C$ and $D$ -

• A. $A$ - No radioactivity ($^{35}S$ ) detected in cells; $B$ - Radioactivity ($^{32}P$) detected in supernatant; $C$ - Radioactivity ($^{35}S$) detected in cells; $D$ - No radioactivity in supernatant.
• B. $A$ - Radioactivity ($^{35}S$) detected in cells; $B$ - No radioactivity ($^{35}P$) detected in supernatant; $C$ - Radioactivity ($^{32}S$) detected in cells; $D$ - No radioactivity in supernatant.
• C. $A$ - No radioactivity ($^{35}S$) detected 1 in cells; $B$ - Radioactivity ($^{35}P$) detected in supernatant; $C$ - Radioactivity ($^{32}C$) Jetected in cells; $D$ - No radioactivity in supernatant.
• D. $A$ - No radioactivity ($^{35}S$) detected in cells; $B$ - Radioactivity ($^{35}P$) detected in supernatant; $C$ - No radioactivity ($^{32}S$) detected in cells; $D$ - Radioactivity in supernatant.

Answer 1

Answer: (C)

Correct answer is (c) $A$ - No radioactivity ($^{35}S$) detected 1 in cells; $B$ - Radioactivity ($^{35}P$) detected in supernatant; $C$ - Radioactivity ($^{32}C$) Jetected in cells; $D$ - No radioactivity in supernatant.