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  4. Alcohol oversetP + I2 arrow X oversetMg , dry ether arrow Y oversetHCHO arrow Z oversetH2 O / H+ arrow 2-methylpropanol In this sequence of reactions, the starting alcohol is

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Q. $Alcohol \, \overset{P + I_{2}}{ \rightarrow } \, X \, \overset{Mg , \, dry \, ether}{ \rightarrow } \, Y \, \overset{HCHO}{ \rightarrow } \, Z \, \overset{H_{2} O / H^{+}}{ \rightarrow } \, 2-methylpropanol$

In this sequence of reactions, the starting alcohol is

NTA AbhyasNTA Abhyas 2020Alcohols Phenols and Ethers

Solution:

Alcohols on reaction with phosphorous iodide to give alkyl chloride. The product formed has a halogen atom attached to the same carbon which was attached to the hydroxy group.

Solution

The alkyl iodide formed reacts with $Mg$ in presence of dry ether to form Grignard reagent, isopropyl magnesium iodide.

Solution

The Grignard reagent on reaction with formaldehyde gives $2-$ methylpropoxide ion.

Solution

$2-$ methylpropoxide ion on acidic hydrolysis finally gives $2-$ methylpropanol.

Solution