Question

$AlCl_{3}$ achieves stability by forming a dimer. In trivalent state the compound is hydrolysed in water. $AlCl_{3}$ in acidified aqueous solution forms

• A. $Al\left(O H\right)_{3}+HCl$
• B. $\left[ Al \left( H _{2} O _{6}\right]^{3+}+3 Cl ^{-}\right.$
• C. $AlCl_{3}.2H_{2}O$
• D. $Al_{2}O_{3}+HCl$

Answer 1

Answer: (B)

$AlCl_{3}$ in acidified aqueous solution forms $\left(\left[A l \left(H_{2} O\right)_{6}\right]\right)^{3 +}$ ion.
$AlCl_{3}+9H_{2}O \rightarrow \left[A l \left(H_{2} O\right)_{6}\right]\left(O H\right)_{3}+3H^{+}+3Cl^{-}$