Question

$Al^{3+}$ has low ionic radius than $Mg^{2+}$ because

• A. $Al^{3+}$ has high nuclear charge than $Mg^{2+}$
• B. Mg atom has less no. of neutrons than Al atom
• C. Mg and Al differ in electronegativity values
• D. Al atom has low ${\mathrm{IE}}_{}$ value than Mg atom

Answer 1

Answer: (A)

Atomic radius is inversely proportional to nuclear attraction. $Al^{3+}$ has low ionic radius than $Mg^{2+}$ therefore $Al^{3+}$ has low ionic radius than $Mg^{2+}$