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Q. Air is blown at the mouth of an open tube of length $25\,cm$ and diameter $2\,cm$. If the velocity of sound in air is $330\, ms^{-1},$ then the emitted frequencies are (in $Hz$)

KEAMKEAM 2011Waves

Solution:

$v = n \lambda $
$n = \frac{v}{2l} = \frac{330}{2 \times 25} = 660\, Hz$
$\left(\because l = \frac{\lambda}{2} \right)$
$n_1 = 2 \times 660=1320\, Hz $
$n_2 = 2 \times 1320=2640\, Hz $