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Physics
Air is blown at the mouth of an open tube of length 25 cm and diameter 2 cm. If the velocity of sound in air is 330 ms-1, then the emitted frequencies are (in Hz)
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Q. Air is blown at the mouth of an open tube of length $25\,cm$ and diameter $2\,cm$. If the velocity of sound in air is $330\, ms^{-1},$ then the emitted frequencies are (in $Hz$)
KEAM
KEAM 2011
Waves
A
660, 1320, 2640
54%
B
660, 1000, 3300
15%
C
302, 664,1320
17%
D
330, 990 1690
12%
E
330,660,990
12%
Solution:
$v = n \lambda $
$n = \frac{v}{2l} = \frac{330}{2 \times 25} = 660\, Hz$
$\left(\because l = \frac{\lambda}{2} \right)$
$n_1 = 2 \times 660=1320\, Hz $
$n_2 = 2 \times 1320=2640\, Hz $