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Q. Air in a cylinder is suddenly compressed by a piston, which is then maintained at the same position. With the passage of time

Thermodynamics

Solution:

From the First Law of Thermodynamics,
$d Q = dU + dW$
Sudden processes are adiabatic, so $d Q =0$
$dU =- dW$
In compression, $dW <0$
So, $dU >0$ which means $dT >0$
With passage of time (i.e. slow process), piston is maintained at the same place. Hence, Volume is constant.
So, P $\alpha$ T.
As temperature decreases with time, pressure decreases too.