Question

$ AgCl+KIKCl+AgI $ In the above reaction as KI is added, the equilibrium is shifted towards right giving more. $ AgI $ precipitate, because

• A. both $ AgCl $ and $ AgI $ are sparingly soluble
• B. the $ {{K}_{sp}} $ of $ AgI $ is lower than $ {{K}_{sp}} $ of $ AgCl $
• C. the $ {{K}_{sp}} $ of $ AgI $ is higher than $ {{K}_{sp}} $ of $ AgCl $
• D. both $ AgCl $ and $ AgI $ have same solubility product

Answer 1

Answer: (B)

On adding KI, the equilibrium $ AgCl+KIKCl+AgI $ is shifted towards right. This means that $ AgI $ is less soluble than $ AgCl $ . In other words. $ {{K}_{sp}} $ of $ AgI $ is less than $ {{K}_{sp}} $ of $ AgCl $ .