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Q. After passing through a polariser a linearly polarised light of intensity $I$ is incident on an analyser making an angle of $30^{\circ}$ with that of the polariser. The intensity of light emitted from the analyser will be :

NEETNEET 2022Wave Optics

Solution:

According to Malus law
$I _2= I _1 \cos ^2 \theta$
Where $I _1$ is incident Polarised light
$I _2= I \cos ^2 30= I \left(\frac{\sqrt{3}}{2}\right)^2$
$ I _2=\frac{3 I }{4}$