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  4. After five half lives percentage of original radioactive atoms left is

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Q. After five half lives percentage of original radioactive atoms left is

Nuclei

Solution:

$N=N_{0}\left(\frac{1}{2}\right)^{n}$
where $n=5$
$\therefore N=\frac{N_{0}}{32}$
$N=3.125 \%$ of $N_{0}$