Question

Adsorption of a gas follows Freundlich adsorption isotherm. In the given plot, x is the mass of the gas adsorbed on mass m of the adsorbent at pressure p. $\frac{x}{m}$ is proportional to

• A. $P^{\frac{1}{4}}$
• B. $P^{2}$
• C. P
• D. $P^{\frac{1}{2}}$

Answer 1

Answer: (D)

$\frac{x}{m}=K\times P^{1 / n}$
$log\frac{x}{m}=logK+\frac{1}{n}logP$
on compairing with $y=mx+c$
$m=\frac{1}{n}=\frac{2}{4}=\frac{1}{2}\Rightarrow n=2$
So, $\frac{x}{m}=K\times P^{1 / 2}$