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Chemistry
Addition of HI on double bond of propene yields isopropyl iodide as major product. It is because the addition proceeds through
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Q. Addition of $HI$ on double bond of propene yields isopropyl iodide as major product. It is because the addition proceeds through
Hydrocarbons
A
More stable carbocation
73%
B
More stable carbanion
8%
C
More stable free radical
10%
D
Homolysis
8%
Solution:
$CH_3CH = CH_2 + \overset{\delta +}{H} - I^- \rightarrow \underset{2^{\circ} \text{carbocation}} {CH_3 \overset{+}{C}H- CH_3 } + I^-$