1. Tardigrade
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  3. Chemistry
  4. Addition of HBr on; CH ≡ C - CH2 - CH = CH2 and CH ≡ C - CH = CH2 separately gives

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Q. Addition of HBr on;
$CH \equiv C - CH_{2} - CH = CH_{2}$ and $CH \equiv C - CH = CH_{2}$ separately gives

Hydrocarbons

Solution:

The first addition will occur on the double bond. Thus,
But in $CH \equiv C - CH = CH_{2},$ he addition will occur at $CH \equiv C $ because the product formed is conjugated alkadiene, which is more stable.

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