1. Tardigrade
  2. Question
  3. Chemistry
  4. According to Raoult's law, relative lowering of vapour pressure for a solution is equal to:

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. According to Raoult's law, relative lowering of vapour pressure for a solution is equal to:

BHUBHU 2001

Solution:

According to Raoult's law' the partial pressure of any volatile, component of a solution at any temperature is equal to the vapour pressure of pure component multiplied by mole fraction of the component in the solution.
$P_{A}=P_{A}^{o} x_{A}$
where, $P_{A}=$ vapour pressure of component $A$
$P_{A}^{o}=$ vapour pressure of pure component
$x_{A}=$ mole fraction of component $A$.
$\frac{P_{A}-P_{A}^{o}}{P_{A}^{o}}=x_{A}$
So, it is equal to the mole fraction of a solute.