1. Tardigrade
  2. Question
  3. Physics
  4. According to Bohr's theory, the energy of an electron in hydrogen atom starts corresponding to n=1,2,3,4 is -13.6 eV ,-3.4 eV ,-1.51 eV and -0.85 eV respectively. In order to obtain emission of Hβ line of Balmer series, the energy that has to be given to a normal hydrogen atom is

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Q. According to Bohr's theory, the energy of an electron in hydrogen atom starts corresponding to $n=1,2,3,4$ is $-13.6 eV ,-3.4 eV ,-1.51 eV$ and $-0.85 eV$ respectively. In order to obtain emission of $H_{\beta}$ line of Balmer series, the energy that has to be given to a normal hydrogen atom is

Atoms

Solution:

The hydrogen atom in the ground state $(-13.6 eV )$ must be excited to the energy level with $n=4($ i.e., $-0.85 eV )$ so as to have $H_{\beta}$ line.