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Q. According to Bernoullis equation
$ \frac{P}{\rho g}+h+\frac{1}{2}\frac{{{v}^{2}}}{g}=\text{constant} $
The terms A, B and C are generally called respectively:

Jharkhand CECEJharkhand CECE 2007

Solution:

According to Bernoullis theorem, in case of steady flow of incompressible and non-viscous liquid through a tube of non-uniform cross-section, the sum of the pressure, the potential energy per unit volume and the kinetic energy per unit volume is same at every point in the tube, i.e.,
$ P+\rho gh+\frac{1}{2}\rho {{v}^{2}}=\text{constant} $
Dividing this expression by
$ \rho g, $ we have $ \frac{P}{\rho g}+\frac{{{v}^{2}}}{2g}+h=\text{constant} $
In this expression $ \frac{P}{\rho g} $
is called the pressure head, $ \frac{{{v}^{2}}}{2g} $
the velocity head and $ h $ the gravitational head.