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Q. According to Arrhenius equation what will be the effect on log k with increase in $ \frac{1}{T} $ ?

CMC MedicalCMC Medical 2015

Solution:

Decrease linearly,
$ k=A{{e}^{-{{E}_{a}}/RT}} $ $ k=\ln A-\frac{{{E}_{a}}}{RT} $ Intercept = ln A Slope = $ -\frac{{{E}_{a}}}{R} $

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