Q. According to Arrhenius equation what will be the effect on log k with increase in $ \frac{1}{T} $ ?
CMC MedicalCMC Medical 2015
Solution:
Decrease linearly,
$ k=A{{e}^{-{{E}_{a}}/RT}} $ $ k=\ln A-\frac{{{E}_{a}}}{RT} $ Intercept = ln A Slope = $ -\frac{{{E}_{a}}}{R} $
