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  4. Acceleration versus time graph of a particle moving in a straight line is as shown in adjoining figure-3.72. If initially particle was at rest. Then corresponding kinetic energy versus time graph will be :

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Q. Acceleration versus time graph of a particle moving in a straight line is as shown in adjoining figure-$3.72$. If initially particle was at rest. Then corresponding kinetic energy versus time graph will be :Physics Question Image

Work, Energy and Power

Solution:

As throughout motion acceleration is positive, speed continuously increases so $K E$ also increases continuously with positive slope. The slope of $K E$ is $=d(K E) / d t=m v a$ hence only possible option is (A).