Question

Acceleration velocity graph of a particle moving in a straight line is as shown in figure. The slope of velocity-displacement graph

• A. increases linearly
• B. decreases linearly
• C. is constant
• D. increases parabolically

Answer 1

Answer: (C)

From the acceleration-velocity graph, we have $a=k \, v \, $ where $k$ is a constant which represents the slope of the given line.
As, $a=v\frac{dv}{ds},$ so $v\frac{dv}{ds}=kv$
or $\frac{dv}{ds}=k=a$ constant
Thus, the slope of the velocity-displacement graph is the same as that of acceleration-velocity. Which is constant.