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Q. $ABCD$ is a convex quadrilateral. $3,4,5$ and $6$ points are marked on the sides $AB , BC , CD$ and DA respectively. Find the number of triangles with vertices on different sides.

Permutations and Combinations

Solution:

The number of triangles with vertices on sides
$AB , BC , CD ={ }^{3} C _{1} \times{ }^{4} C _{1} \times{ }^{5} C _{1}$
Similarly for other cases
$\therefore $ The total number of triangles
$={ }^{3} C _{1} \times{ }^{4} C _{1} \times{ }^{5} C _{1}+{ }^{3} C _{1} \times{ }^{4} C _{1} \times{ }^{6} C _{1}$
$+{ }^{3} C _{1} \times{ }^{5} C _{1} \times{ }^{6} C _{1} +{ }^{4} C _{1} \times{ }^{5} C _{1} \times{ }^{6} C _{1}=342$