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Q. $AB$ and $CD$ are two slabs. The medium between the slabs has refractive index as shown in the figure. Minimum angle of incidence (in degrees) at $Q$ , so that the ray is totally reflected by both the slabs is

a

Question

NTA AbhyasNTA Abhyas 2020Ray Optics and Optical Instruments

Solution:

Critical angles at 1 and 2
Solution
$\theta_{c_1}=\sin ^{-1}\left(\frac{\mu_1}{\mu_2}\right)=\sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)=45^0$
$\theta_{c_2}=\sin ^{-1}\left(\frac{\mu_3}{\mu_2}\right)=\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right)=60^0$
Therefore, minimum angle of incidence for total internal reflection to take place on both slabs should be 600