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Q. A Zener diode of Zener break-down voltage $10 \, V$ is connected as shown in the figure. Current through Zener diode is

Question

NTA AbhyasNTA Abhyas 2020Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Solution
If we consider break down in Zener diode, then potential across $R_{3}$ will be $10V$ and $R_{1}$ will be $2V$ .
So current in $R_{3}$ will be $i_{3}=\frac{10}{1500}=\frac{2}{300}A$
and current in $R_{1}$ will be $i_{1}=\frac{2}{500}A$
$\Rightarrow i_{1} < i_{3}$ , which is not possible
$\Rightarrow $ The potential difference across the Zener diode does not reach to break down voltage. So no current will flow through the reverse-biased Zener diode.