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Q. A x molal solution of compound in benzene has a mole fraction of solute equal to 0.2. The value of x is

Surface Chemistry

Solution:

The given solution contains that $x$ moles of solute in $1 kg$ of benzene
$\therefore $ Moles of benzene $=\frac{1000\,g}{78\,g\,mol^{-1}}=12.8\,mol$
$\therefore 0.2=\frac{x}{x+12.8}; 5=1+\frac{12.8}{x}$
$\frac{12.8}{x}=4 ; x=\frac{12.8}{4}$
$=3.2$