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  4. A ( x 1, y 1), B ( x 2, y 2) and C ( x 3, y 3) are three non-collinear points in cartesian plane. Number of parallelograms that can be drawn with these three points as vertices is -

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Q. $A \left( x _1, y _1\right), B \left( x _2, y _2\right)$ and $C \left( x _3, y _3\right)$ are three non-collinear points in cartesian plane. Number of parallelograms that can be drawn with these three points as vertices is -

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Solution:

Correct answer is (c) three

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