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Q. A wore of certain material is stretched slowly by $10 \%$. Its new resistance and specific resistance becomes respectively

KCETKCET 2022Current Electricity

Solution:

Let $1_{1}=100,1_{2}=110$
$R \propto 1^{2}$
$\frac{ R _{2}}{ R _{1}}=\left(\frac{1_{2}}{1_{1}}\right)^{2}=\left(\frac{110}{100}\right)^{2}=1.21$
$ R _{2}=1.21 R _{1}$
Specific resistance remains same