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  4. A woman of 50 kg mass is standing in an elevator. Suddenly, the cable of the elevator breaks and the elevator begins to fall freely. The force exerted by the floor of the elevator on the woman is

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Q. A woman of $50\, kg$ mass is standing in an elevator. Suddenly, the cable of the elevator breaks and the elevator begins to fall freely. The force exerted by the floor of the elevator on the woman is

Laws of Motion

Solution:

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$50 g-N=50 a$ or $N=50(g-a)$
If $a=g,$ then $N=0 .$