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  4. A wire PQR is bent as shown in figure and is placed in a of uniform magnetic field B. The length of PQ = QR = I. A current/ amp flows through the wire as shown. The magnitude of the force on PQ and QR will be

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Q. A wire $PQR$ is bent as shown in figure and is placed in a of uniform magnetic field $B$. The length of $PQ = QR = I$. A current/ amp flows through the wire as shown. The magnitude of the force on $PQ$ and $QR$ will bePhysics Question Image

Jharkhand CECEJharkhand CECE 2008

Solution:

The Lorentz force acting on the curredt carrying conductor in the magnetic field
$ F=IBl \sin \, \theta$
Since, wire $PQ$ is parallel to the direction of magnetic field,
then $\theta =0, $
$\therefore F_{PQ}=IBl \sin \, 0^{\circ} =0 $
Also, wire $QR$ is perpendicular to the direction of magnetic field, then $\theta=90 ^{\circ}$
$\therefore F_{QR}=IBl \sin \, 90^{\circ} =IBl$