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  4. A wire PQR is bent as shown in figure and is placed in a region of uniform magnetic field B. The length of PQ = QR = I. A current I ampere flows through the wire as shown. The magnitude of the force on PQ and QR will be

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Q. A wire PQR is bent as shown in figure and is placed in a region of uniform magnetic field B. The length of PQ = QR = I. A current I ampere flows through the wire as shown. The magnitude of the force on PQ and QR will bePhysics Question Image

CMC MedicalCMC Medical 2009

Solution:

The Lorentz force acting on the current carrying conductor in the magnetic field is $ F=IBl\,\sin \theta $ Since, wire PQ is parallel to the direction of magnetic field, then $ \theta =0, $ $ \therefore $ $ {{F}_{PQ}}=IBl\,\sin 0{}^\circ =0 $ Also, wire QR is perpendicular to the direction of magnetic field, then $ \theta =90{}^\circ . $ $ \therefore $ $ {{F}_{QR}}=IBl\,\sin 90{}^\circ =IBl $