Q.
A wire of resistance $R$ is bent to form a square $ABCD$ as shown in the figure. The effective resistance between $E$ and $C$ is : ($E$ is mid-point of arm $CD$)
Solution:
$\frac{1}{R_{eq}} = \frac{8}{7R} + \frac{8}{R}$
$\frac{1}{r_{eq}} = \frac{8+56}{7R}$
$R_{eq} = \frac{7R}{64}$
