Q. A wire of resistance $ 18\,\Omega $ is divided into three equal parts. These parts are connected in side of triangle, the equivalent resistance of any two corners of triangle will be
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Solution:
To find equivalent resistance across BC, AB and AC are in series
$ R'=6+6=12\,\Omega $
$ 12\,\Omega $ and $ 6\,\Omega $
is in parallel Total resistance,
$ R=\frac{12\times 6}{12+6} $
$ R=\frac{72}{18}=4\Omega $