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Q. A wire of mass 100 g, length 1 m and current 5 A is balanced in mid air by a magnetic field B, then find the value of B.

AIIMSAIIMS 2012Moving Charges and Magnetism

Solution:

Here,m = 100 g = 10-1 kg, l = 1 m, I = 5 A
For a wire balanced midway air by a magnetic field is
mg = IlB.
or $\, B=\frac{mg}{Il}$
$\, =\frac{10^{-1}\times10}{5\times1}$
B = 0.2 T.