Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A wire of length $L$ and 3 identical cells of negligible internal resistances are connected in series. Due to the current, the temperature of the wire due to the current, the temperature of the wire is raised by $\Delta T$ is a time $t$. A number $N$ of similar cells is now connected in series with a wire of the same material and cross-section but of length $2 L$. The temperature of the wire is raised by the same amount $\Delta T$ in the same time $t$. The value of $N$ is

Current Electricity

Solution:

As, $R=\frac{\rho L}{A} ; R_{1}=\frac{\rho 2 L}{A}=2 R$
$m=A L d ;\, m_{1}=A 2 L d=2 m$
where $d$ is density.
Now, $\frac{(3 V)^{2} t}{R}=m c \Delta T$ ...(i)
and $\frac{(N V)^{2} t}{2 R}=2 m c \Delta T$ ...(ii)
Solving Eqs. (i) and (ii), we get $N=6$