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Q. A wire connected in the left gap of a meter bridge balance a $10 \,\Omega$ resistance in the right gap to a point, which divides the bridge wire in the ratio $3 :2$. If the length of the wire is $1\, m$. The length of one ohm wire is

Current Electricity

Solution:

Here, $\frac{R}{S}=\frac{3}{2}$, $S=10\,\Omega$
$\therefore R=\frac{3}{2}\times S=\frac{3}{2}\times10=15\,\Omega$
As the length of wire is $1\, m$.
$\therefore $ length of one ohm wire $=1/5=0.067\,m$