1. Tardigrade
  2. Question
  3. Physics
  4. A wire can be broken by applying a load of 30 kg-wt. The force required to break the wire of twice the diameter is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A wire can be broken by applying a load of $30\, kg-wt$. The force required to break the wire of twice the diameter is

Mechanical Properties of Solids

Solution:

Breaking Stress $=\frac{\text { Force }}{\text { Area }}$
$\therefore $ wire is same, breaking stress is constant
$F \propto A$
$\therefore \frac{F_{1}}{F_{2}}=\frac{A_{1}}{A_{2}} =\frac{\pi D_{1}^{2}}{4} \times \frac{4}{\pi D_{2}^{2}}=\left(\frac{D_{1}}{D_{2}}\right)^{2}=\frac{1}{4}$
$\therefore F_{2}=40 \times 30=120 \,kg \,wt$